Pełnotekstowe zasoby PLDML oraz innych baz dziedzinowych są już dostępne w nowej Bibliotece Nauki.
Zapraszamy na https://bibliotekanauki.pl
Preferencje help
Polish version English version Język
Widoczny [Schowaj] Abstrakt
Liczba wyników

Znaleziono wyników: 3

Liczba wyników na stronie
first rewind previous Strona / 1 next fast forward last

Wyniki wyszukiwania

help Sortuj według:

help Ogranicz wyniki do:
first rewind previous Strona / 1 next fast forward last
1
Artykuł dostępny w postaci pełnego tekstu - kliknij by otworzyć plik
Content available

Trees with α-labelings and decompositions of complete graphs into non-symmetric isomorphic spanning trees

100%
Kubesa M.
Discussiones Mathematicae Graph Theory
|
2005
|
tom 25
|
nr 3
311-324
EN
We examine constructions of non-symmetric trees with a flexible q-labeling or an α-like labeling, which allow factorization of $K_{2n}$ into spanning trees, arising from the trees with α-labelings.
2
Content available remote

Rectangular table negotiation problem revisited

63%
Froncek D., Kubesa M.
Open Mathematics
|
2011
|
tom 9
|
nr 5
1114-1120
EN
We solve the last missing case of a “two delegation negotiation” version of the Oberwolfach problem, which can be stated as follows. Suppose we have two negotiating delegations with n=mk members each and we have a seating arrangement such that every day the negotiators sit at m tables with k people of the same delegation at one side of each table. Every person can effectively communicate just with three nearest persons across the table. Our goal is to guarantee that over the course of several days, every member of each delegation can communicate with every member of the other delegation exactly once. We denote by H(k, 3) the graph describing the communication at one table and by mH(k, 3) the graph consisting of m disjoint copies of H(k, 3). We completely characterize all complete bipartite graphs K n,n that can be factorized into factors isomorphic to G =mH(k, 3) for k ≡ 2 (mod 4) by showing that the necessary conditions n=mk and m ≡ 0 mod(3k−2)/4 are also sufficient. This results complement previous characterizations for k ≡ 0, 1, 3 (mod 4) to settle the problem in full.
3
Artykuł dostępny w postaci pełnego tekstu - kliknij by otworzyć plik
Content available

Problem presented at the workshop in Krynica 2004

63%
Kubesa M., Froncek D.
Discussiones Mathematicae Graph Theory
|
2006
|
tom 26
|
nr 2
351
first rewind previous Strona / 1 next fast forward last
JavaScript jest wyłączony w Twojej przeglądarce internetowej. Włącz go, a następnie odśwież stronę, aby móc w pełni z niej korzystać.